Fixed blog post: Puzzled Programmers
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@ -16,7 +16,7 @@ machines:
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name: None
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---
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One of books I used to have a copy of (and perhaps still do, in the bowels of my storage unit) was "Puzzled Programmers"
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A book I used to have a copy of (and perhaps still do, in the bowels of my storage unit) was "Puzzled Programmers"
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by Michael Wiesenberg. It was published by Microsoft Press in 1987, and I recently rediscovered an online copy in the
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[Internet Archive's](https://archive.org) [Open Library](https://openlibrary.org):
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@ -46,13 +46,13 @@ of the programs presented in the solution to Puzzle 5.
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-------------------------------------------------------------------------------
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*Apple Pascal
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This almost seemed like an invitation to try my hand at Puzzle #5, and to see how a PCjs "machine" fared.
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This almost seemed like an invitation to try my hand at Puzzle #5 and see how a PCjs "machine" compared.
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### A Pleasant Fourthsum
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I skipped ahead to page 27, "Puzzle 5: A Pleasant Fourthsum", and started reading. I have to admit that the story
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completely failed to interest me. There were lots of irrelevant details about a delicious breakfast that this imaginary
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bunch of successful twenty-somethings were enjoying, when suddenly one of them says:
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bunch of successful twenty-somethings was enjoying, when suddenly one of them says:
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"Before we get into the future of languages at I-Q, I've got a great computer puzzle for everyone."
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@ -143,10 +143,10 @@ main()
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{
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int pwr[10], /* the fourth power of each digit */
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h, /* the digit in the thousands position */
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h000, /* h * 1000, that is, the value of the number
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h000, /* h * 1000, that is, the value of the number
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in the thousands position */
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i, /* the digit in the hundreds position */
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i00, /* i * 100, that is, the value of the number
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i00, /* i * 100, that is, the value of the number
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in the hundreds position */
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j, /* the digit in the tens position */
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j0, /* i * 10, that is, the value of the number
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@ -166,9 +166,8 @@ main()
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/* tens digit */
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partsum = h000 + i00 + j0;
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part4ths = pwr[h] + pwr[i] + pwr[j];
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for ( k = 0; k <= 9; k++) { /* ones digit */
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sum = partsum + k; /* this produces the four-digit
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number */
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for ( k = 0; k <= 9; k++) { /* ones digit */
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sum = partsum + k; /* this produces the four-digit number */
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if (part4ths + pwr[k] == sum) {
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if (!l) printf("%d = %d^4 + %d^4 + %d^4 + %d^4\n",
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sum, h, i, j, k);
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