Updated VT100 keymap
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c78317c056
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6 changed files with 457 additions and 389 deletions
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@ -939,6 +939,7 @@ CPUState.prototype.checkINTR = function()
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{
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if ((this.intFlags & CPUDef.INTFLAG.INTR) && this.getIF()) {
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var bRST = CPUDef.OPCODE.RST0 | ((this.intFlags & CPUDef.INTFLAG.INTL) << 3);
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this.intFlags &= ~CPUDef.INTFLAG.HALT;
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this.clearINTR();
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this.clearIF();
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this.aOps[bRST].call(this);
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@ -1096,16 +1097,30 @@ CPUState.prototype.stepCPU = function(nMinCycles)
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do {
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if (this.intFlags) {
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if (this.checkINTR()) {
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if (!nMinCycles) {
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this.assert(DEBUGGER); // nMinCycles of zero should be generated ONLY by the Debugger
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if (DEBUGGER) {
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this.println("interrupt dispatched");
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break;
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}
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}
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/*
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* We no longer call checkINTR() if the Debugger is single-stepping; you'll have to let the
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* CPU run with a "g" (or a "p" on a call instruction) if you want interrupts to be processed.
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*/
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if (nMinCycles) {
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/*
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* NOTE: If checkINTR() returns true, it also clears INTFLAG.HALT, so we don't have to worry
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* about the INTFLAG.HALT code below triggering.
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*/
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this.checkINTR();
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/*
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* If the Debugger is running, consider some new notification mechanism(s) regarding interrupt
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* dispatches; the following code no longer applies, due to changes above.
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*
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* if (!nMinCycles && this.checkINTR()) {
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* this.assert(DEBUGGER); // nMinCycles of zero should be generated ONLY by the Debugger
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* if (DEBUGGER) {
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* this.println("interrupt dispatched");
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* break;
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* }
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* }
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*/
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}
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else if (this.intFlags & CPUDef.INTFLAG.HALT) {
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if (this.intFlags & CPUDef.INTFLAG.HALT) {
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/*
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* As discussed in opHLT(), the CPU is never REALLY halted by a HLT instruction; instead,
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* opHLT() sets CPUDef.INTFLAG.HALT, signalling to us that we're free to end the current burst
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