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04-04.md
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04-04.md
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@ -9,16 +9,16 @@ long. That means that it can never execute in less than 24 cycles even
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if the 4-byte prefetch queue is full when it starts, since 6 instruction
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bytes would still remain to be fetched, at 4 cycles per fetch. If the
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prefetch queue is empty at the start, the sequence *could* take 40
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cycles. In short, thanks to instruction fetching, the code won’t run at
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cycles. In short, thanks to instruction fetching, the code won't run at
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its documented speed, and could take up to four times longer than it is
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supposed to.
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Why does Intel document Execution Unit execution time rather than
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overall instruction execution time, which includes both instruction
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fetch time and Execution Unit (EU) execution time? Well, instruction
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fetching isn’t performed as part of instruction execution by the
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fetching isn't performed as part of instruction execution by the
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Execution Unit, but instead is carried on in parallel by the Bus
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Interface Unit (BIU) whenever the external data bus isn’t in use or
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Interface Unit (BIU) whenever the external data bus isn't in use or
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whenever the EU runs out of instruction bytes to execute. Sometimes the
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BIU is able to use spare bus cycles to prefetch instruction bytes before
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the EU needs them, so in those cases instruction fetching takes no time
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@ -34,14 +34,14 @@ overall execution time of the following instructions.
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 *In other words, while the execution time for a given instruction is constant, the fetch time for that instruction depends heavily on the context in which the instruction is executing—the amount of prefetching the preceding instructions allowed—and can vary from a full 4 cycles per instruction byte to no time at all.*
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------------------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
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As we’ll see later, other cycle-eaters, such as DRAM refresh and display
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As we'll see later, other cycle-eaters, such as DRAM refresh and display
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memory wait states, can cause prefetching variations even during
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different executions of the same code sequence. Given that, it’s
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different executions of the same code sequence. Given that, it's
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meaningless to talk about the prefetch time of a given instruction
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except in the context of a specific code sequence.
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So now you know why the official instruction execution times are often
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wrong, and why Intel can’t provide better specifications. You also know
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wrong, and why Intel can't provide better specifications. You also know
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now why it is that you must time your code if you want to know how fast
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it really is.
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@ -57,16 +57,16 @@ the timer can cause problems.
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Some slight prefetch queue-induced inaccuracy usually exists even when
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the Zen timer is used to time longer code sequences, since the calls to
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the Zen timer usually alter the code’s prefetch queue from its normal
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the Zen timer usually alter the code's prefetch queue from its normal
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state. (Branches—jumps, calls, returns and the like—empty the prefetch
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queue.) Ideally, the Zen timer is used to measure the performance of an
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entire subroutine, so the prefetch queue effects of the branches at the
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start and end of the subroutine are similar to the effects of the calls
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to the Zen timer when you’re measuring the subroutine’s performance.
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to the Zen timer when you're measuring the subroutine's performance.
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Another way in which the prefetch queue cycle-eater complicates the use
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of the Zen timer involves the practice of timing the performance of a
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few instructions over and over. I’ll often repeat one or two
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few instructions over and over. I'll often repeat one or two
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instructions 100 or 1,000 times in a row in listings in this book in
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order to get timing intervals that are long enough to provide reliable
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measurements. However, as we just learned, the actual performance of any
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@ -84,12 +84,12 @@ always empty, execution time should work out to about 4 cycles per byte,
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or 8 cycles per **SHR,** as shown in Figure 4.3. (Figure 4.3 illustrates
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the relationship between instruction fetching and execution in a
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simplified way, and is not intended to show the exact timings of 8088
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operations.) That’s quite a contrast to the official 2-cycle execution
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operations.) That's quite a contrast to the official 2-cycle execution
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time of **SHR**. In fact, the Zen timer reports that Listing 4.5
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executes in 1.81µs per byte, or slightly *more* than 4 cycles per byte.
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(The extra time is the result of the dynamic RAM refresh cycle-eater,
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which we’ll discuss shortly.) Going by Listing 4.5, we would conclude
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that the “true” execution time of **SHR** is 8.64 cycles.
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which we'll discuss shortly.) Going by Listing 4.5, we would conclude
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that the "true" execution time of **SHR** is 8.64 cycles.
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**LISTING 4.5 LST4-5.ASM**
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@ -124,20 +124,20 @@ that the “true” execution time of **SHR** is 8.64 cycles.
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**Figure 4.3** *Execution and instruction prefetching sequence for
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Listing 4.5.*
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Now let’s examine Listing 4.6. Here each **SHR** follows a **MUL**
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Now let's examine Listing 4.6. Here each **SHR** follows a **MUL**
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instruction. Since **MUL** instructions take so long to execute that the
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prefetch queue is always full when they finish, each **SHR** should be
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ready and waiting in the prefetch queue when the preceding **MUL** ends.
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As a result, we’d expect that each **SHR** would execute in 2 cycles;
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As a result, we'd expect that each **SHR** would execute in 2 cycles;
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together with the 118-cycle execution time of multiplying 0 times 0, the
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total execution time should come to 120 cycles per **SHR/MUL** pair, as
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shown in Figure 4.4. And, by God, when we run Listing 4.6 we get an
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execution time of 25.14 µs per **SHR/MUL** pair, or *exactly* 120
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cycles! According to these results, the “true” execution time of **SHR**
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cycles! According to these results, the "true" execution time of **SHR**
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would seem to be 2 cycles, quite a change from the conclusion we drew
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from Listing 4.5.
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The key point is this: We’ve seen one code sequence in which **SHR**
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The key point is this: We've seen one code sequence in which **SHR**
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took 8-plus cycles to execute, and another in which it took only 2
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cycles. Are we talking about two different forms of **SHR** here? Of
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course not—the difference is purely a reflection of the differing states
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